找出最耗CPU的java线程和代码
所属分类 java
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写一个耗cpu的Java代码 模拟一下 cputest.java 代码见最后
编译运行cputest
javac cputest.java
java cputest
找出cputest 对应的进程id
ps aux|grep cputest
ps aux|grep cputest |grep -v 'grep'
ps aux|grep cputest |grep -v 'grep'|awk '{print $2}'
pid 24271
使用top命令找出最耗 cpu的线程
top -p 24271 -H
PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND
24272 root 20 0 2461160 25708 11252 S 45.5 1.4 11:17.99 java
24280 root 20 0 2461160 25708 11252 S 0.3 1.4 0:00.51 java
24271 root 20 0 2461160 25708 11252 S 0.0 1.4 0:00.00 java
24273 root 20 0 2461160 25708 11252 S 0.0 1.4 0:00.02 java
24274 root 20 0 2461160 25708 11252 S 0.0 1.4 0:00.00 java
24275 root 20 0 2461160 25708 11252 S 0.0 1.4 0:00.00 java
24276 root 20 0 2461160 25708 11252 S 0.0 1.4 0:00.00 java
24277 root 20 0 2461160 25708 11252 S 0.0 1.4 0:00.01 java
24278 root 20 0 2461160 25708 11252 S 0.0 1.4 0:00.01 java
24279 root 20 0 2461160 25708 11252 S 0.0 1.4 0:00.00 java
24370 root 20 0 2461160 25708 11252 S 0.0 1.4 0:00.00 java
最耗 cpu的线程ID 为 24272
转换成16进制
printf "%x\n" 24272
5ed0
使用jstack 打印 线程堆栈
jstack 24271
找到 5ed0 对应的线程
nid=0x5ed0
"main" #1 prio=5 os_prio=0 tid=0x00007fb658009000 nid=0x5ed0 waiting on condition [0x00007fb660ca5000]
java.lang.Thread.State: TIMED_WAITING (sleeping)
at java.lang.Thread.sleep(Native Method)
at cputest.main(cputest.java:31)
cputest.java
public class cputest {
private static final long MAX_SEQ = 10000000;
private static final long SLEEP_TIME = 10;
private static final long SLEEP_TIME_MAX = 1000;
public static void main(String[] args) throws Exception {
long sleepTime = SLEEP_TIME;
if(args.length>0){
try{
sleepTime = Long.parseLong(args[0]);
}catch(Throwable e){
// do nothing
}
}
if(sleepTime<=2 || sleepTime> SLEEP_TIME_MAX){
sleepTime = SLEEP_TIME_MAX;
}
System.out.println("MAX_SEQ="+MAX_SEQ);
System.out.println("sleepTime="+sleepTime);
boolean flag = true;
long seq = 0;
while(flag){
seq++;
if(seq>MAX_SEQ){
seq = 0;
Thread.sleep(sleepTime);
}
}
}
}
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