scala 模式匹配
所属分类 scala
浏览量 659
scala 模式匹配 类似于Java中的switch
case分支顺序匹配 匹配成功则执行 匹配不成功,继续匹配
如果所有case都不匹配,执行case _分支,类似于Java switch 中 default语句
常量模式匹配
类型匹配模式
case class模式
模式守卫 在模式后面加上if判断语句
Option匹配
package demo
case class Pet(id:Int,name:String){
}
object PatternMatchDemo {
def main(args: Array[String]) {
println(constantPatternMatch(3))
println(constantPatternMatch(true))
println(constantPatternMatch("test"))
println(constantPatternMatch(null))
println(constantPatternMatch(Nil))
println(constantPatternMatch(9))
println(typePatternMatch(3))
println(typePatternMatch("hello"))
println(typePatternMatch(3.3))
println(typePatternMatch(null))
val map = Map(("a", 1), ("b", 2))
optionMatch(map,"a");
optionMatch(map,"b");
optionMatch(map,"c");
val pet = new Pet(1,"cat")
caseClassMatch(pet);
caseClassMatch(1);
println(abs(1));
println(abs(0));
println(abs(-1));
}
def constantPatternMatch(x: Any) = x match {
case 3 => "int 3"
case true => "bool true"
case "test" => "string test"
case null => "null"
case Nil => "Nil empty list"
case _ => "other"
}
def typePatternMatch(t: Any) = t match {
case t: String => "String"
case t: Int => "Integer"
case t: Double => "Double"
case _ => "Other Type"
}
def optionMatch(m: Map[String, Int],key: String) = m.get(key) match {
case Some(x) => println(x)
case None => println("notExist")
}
def caseClassMatch(x: Any) = x match {
case Pet(id,name) => println(id+","+name)
case _ => println("other")
}
def abs(num: Int): Int = {
num match {
case i if i >= 0 => i
case i if i < 0 => -i
}
}
}
上一篇
下一篇
Scala object 伴生对象
Scala中apply的用法
大数据工程师入门概述
scala Option Some None
scala 类型系统
Scala 构造函数